There is no requirement in the question. I'll calculate the area of the rectangle to help you with this question.
Answer:
[tex]A=15\ cm^2[/tex]
Step-by-step explanation:
System of Equations
Let's call y to the length of a rectangle, x to its width. There are two conditions that will help us to solve for x and y.
- The length is four less than three times the width. That is written as:
[tex]y=3x-4[/tex]
- The perimeter of the rectangle is 16 cm. The equation for this condition is:
[tex]2x+2y=16[/tex]
Divide by 2:
[tex]x+y=8[/tex]
To solve the system, we'll substitute the y in the first equation into the second:
[tex]x+3x-4=8[/tex]
Joining like terms:
[tex]4x=8+4[/tex]
Solving:
[tex]x=12/4=3[/tex]
Find the value of y:
[tex]y=3x-4=3*3-4=9-4=5[/tex]
Thus, the length of the rectangle is 5 cm and its width is 3 cm. The area is calculated as:
[tex]A=xy=3\ cm\cdot 5\ cm=15\ cm^2[/tex]
[tex]\boxed{A=15\ cm^2}[/tex]
