Answer:
Area of larger rectangle = 1½ = 1.5 in²
Step-by-step explanation:
The section consists of 3 small squares that has an area = [tex] \frac{3}{16} in^2 [/tex].
Area of 3 small squares = [tex] \frac{3}{16} in^2 [/tex]
Area of 1 small square = [tex] \frac{3}{16} [/tex] ÷ 3
= [tex] \frac{3}{16} * \frac{1}{3} [/tex]
= [tex] \frac{3*1}{16*3} = \frac{1}{16} [/tex]
The larger rectangle has 24 small squares of equal sizes
Area of larger rectangle = area of 1 small square * 24
= [tex] \frac{1}{16} * 24 [/tex]
[tex] = \frac{24}{16} = \frac{3}{2} [/tex]
Area of larger rectangle = 1½ = 1.5 in²
