contestada

If the area of a square is 33 square inches, which is greater: the length of a side of the of a side of the square to the nearest tenth of an inch or the square root of 40?

Respuesta :

Answer:

square root of 40  is greater than side of the square

Step-by-step explanation:

First we find square root of 40

[tex]\sqrt{40} = 6.325[/tex]

Now

given

area of a square is 33 square inches

we know area of square is side square

area of square  = [tex]side^2[/tex]

[tex]side^2 = 33\\\sqrt{side^2} = \sqrt{33}\\side = 5.745[/tex]

Thus, we see length side of square is 5.7 inches

and square root of 40 is 6.325

since

6.325 > 5.7

hence square root of 40  is greater