Answer:
square root of 40 is greater than side of the square
Step-by-step explanation:
First we find square root of 40
[tex]\sqrt{40} = 6.325[/tex]
Now
given
area of a square is 33 square inches
we know area of square is side square
area of square = [tex]side^2[/tex]
[tex]side^2 = 33\\\sqrt{side^2} = \sqrt{33}\\side = 5.745[/tex]
Thus, we see length side of square is 5.7 inches
and square root of 40 is 6.325
since
6.325 > 5.7
hence square root of 40 is greater