Answer and Step-by-step explanation:
Let
Compost lb per bag = x1 = 30
Compost cost per lb = 0.05
Sewage lb per bag = x2 = 40
Sewage cost per lb = 0.04
Minimize cost = 0.5 x1 + 0.4 x2
Constraints:
Bags of manure labeled “not less than 60 lb dry weight”
X1 + x2 ≥ 60
X1 ≥ 30
X2 ≥ 40
At x1 = 30 and x2 = 40
C = 0.05(30) + .04(40)
= 1.5+ 1.6
=$3.1
At x1= 60 and x2 = 0
C= 0.05(60) + 0.04(0)
= 3 + 0
=$3.00
At x1 = 30 and x2= 30
C = 0.05(30) + 0.04(30)
= 1.5 + 1.2
=$2.7