Respuesta :
Answer:
Explanation:
The first step in order to solve this particular question is to make sure that the two reactions given in the question is balanced. Therefore, we have;
Reaction 1: C6H12O6 -----------------------------> 2 C2H5OH + 2 CO2.
Reaction 2: C6H12O6 ------------------------------> 2 C2H3CO2H + 2 H2O.
Next, we determine the number of moles of water and that of glucose. Recall that we are given from the question that the open flow reactor = 4000 kg of a 12% glucose-water solution flows in that is to say the percentage for water is [100% - 12% = 88%]. Also, the molar mass of water = H₂O = 18 kg/kmol and that for glucose =180 kg/kmol.
Number of moles of water = (4000 kg × 88%) ÷ 18 = 195.6 kmol.
Number of moles of glucose= (4000kg × 12%) ÷ 180 = 2.67 kmol.
Next thing to do is to determine the number of moles in the unreacted glucose . Therefore, the 90 kg of unreacted glucose ÷ 180kg/kmol = 0.5 kmol.
So, we have that During fermentation, 120 kg of carbon dioxide is produced. Thus, the number of kmol = 120kg÷ 44kg/mol = 2.73kmol.
For reaction 1, we have 2 moles of CO₂ that is to say the extent of the reaction = 2.73kmol / 2 moles of CO₂ = 1.365 kmol.
For reaction 2, we have 2 moles of CO₂ that is to say the extent of the reaction = 2.67kmol - 0.5 kmol - 1.365kmol = 0.805 kmol.
For both reaction, the kmol for outflow of glucose = 2.73 kmol.
Also, 2 × 0.805 + 1.365 × 0 = 1.61kmol.
Hence, 195.6 kmol + 1.61 =197.21 kmol.
The mass of ethanol = 46.1 kg/kmol × 2.73 kmol = 125.853 kg.
The weight percent of ethanol has been 29.72%, and the percent mass of propionic acid has been 47.79%.
The balanced chemical equations of the reactions have been:
[tex]\rm C_6H_1_2O_6\;\rightarrow\;2\;C_2H_5OH\;+\;2\;CO_2[/tex]
[tex]\rm C_6H_1_2O_6\;\rightarrow\;2\;C_2H_3CO_2H\;+\;2\;H_2O[/tex]
The solution has consisted of 12% glucose.
Water in the solution = 88%
The mass of the solution = 4000 kg.
The moles of glucose = 12% of 4000 kg
Moles of glucose = [tex]\rm \dfrac{12}{100}\;\times\;4000\;\times\;\dfrac{1}{180\;g/mol}[/tex]
Moles of glucose = 2.67 kmol.
Moles of water = 88 % of 4000 kg
Moles of water = [tex]\rm \dfrac{88}{100}\;\times\;4000\;\times\;\dfrac{1}{18\;g/mol}[/tex]
Moles of water = 195.6 kmol.
The unreacted glucose in the mixture = 90 kg
Moles of unreacted glucose:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of unreacted glucose = [tex]\rm \dfrac{90\;\times\;1000\;g}{180\;g/mol}[/tex]
Moles of unreacted glucose = 0.5 kmol
The mass of carbon dioxide produced = 120 kg.
Moles of carbon dioxide produced = [tex]\rm \dfrac{120\;\times\;1000\;g}{44\;g/mol}[/tex]
Moles of carbon dioxide produced = 2.73 kmol
Since 1 mole of glucose produces 2 moles of carbon dioxide.
2.73 kmol of carbon dioxide has been produced from 1.365 kmol of glucose.
The moles of ethanol produced by reaction 1 = 2 moles/ mole glucose.
The glucose present has been 2.67 kmol.
The ethanol produced = 5.34 kmol.
Moles of propionic acid produced = 5.34 kmol.
The mass of 5.34 kmol ethanol = Moles × molecular weight
The mass of ethanol produced = 5.34 × 1000 × 46.07g/mol
The mass of ethanol produced = 246.0138 kg.
The mass of propionic acid produced = 5.34 × 1000 × 74.08 g/mol
The mass of propionic acid produced = 395.5872 kg.
The mass of water produced = 5.34 × 1000 × 18 g/mol
The mass of water produced = 96.12 kg.
The remained glucose = 90 kg
The total mass in the reactor:
= Mass of glucose + water + propionic acid + ethanol
= 90 + 96.12 + 395.5872 + 246.0138 kg
= 827.721 kg.
- % Mass of ethanol = [tex]\rm \dfrac{Mass\;of\;ethanol}{Total\;mass}\;\times\;100[/tex]
% Mass of ethanol = [tex]\rm \dfrac{246.0138}{827.721}\;\times\;100[/tex]
% Mass of ethanol = 29.72%
- % Mass of Propionic acid = [tex]\rm \dfrac{Mass\;of\;propionic\;acid}{Total\;mass}\;\times\;100[/tex]
% Mass of Propionic acid = [tex]\rm \dfrac{395.5872}{827.721}\;\times\;100[/tex]
% Mass of Propionic acid = 47.79 %.
The weight percent of ethanol has been 29.72%, and the percent mass of propionic acid has been 47.79%.
For more information about weight percent, refer to the link:
https://brainly.com/question/18204076
