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Suppose number of hours employees work in a week at a company are normally distributed with an unknown population mean and a population standard deviation of 2 hours. A random sample of 65 employees weekly hours is taken. These gave a sample mean time of 39 hours. Find the error bound (EBM) of the confidence interval with a 95% confidence level. A 2 by 5 z-table.

Respuesta :

brandonts2006

Answer:

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Step-by-step explanation:

Answer:

0.49

Step-by-step explanation:

We can use the formula to find the error bound:

EBM=(zα/2)(σ/√n)

We know that σ=2 and n=65. We are also given that the confidence level (CL) is 95%, or 0.95. So, we can calculate alpha (α).

α=1−CL

=1−0.95

=0.05

Since α=0.05, we know that α2=0.05/2=0.025. The value of z0.025 is 1.960.

Now we can substitute the values into the formula to find the error bound.

EBM=(zα/2)(σ/√n)

=(1.960)(2/√65)

≈(1.960)(0.248)

≈0.49

So, the error bound (EBM) is 0.49.

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