Answer:
[tex]y'=\frac{-5}{(3x+2)^2}[/tex]
Step-by-step explanation:
Step 1: Write equation
[tex]y=\frac{2x+3}{3x+2}[/tex]
Step 2: Find derivative
- Quotient Rule: [tex]y'=\frac{(3x+2)(2)-(3)(2x+3)}{(3x+2)^2}[/tex]
- Simplify: [tex]y'=\frac{(6x+4)-(6x+9)}{(3x+2)^2}[/tex]
- Simplify: [tex]y'=\frac{-5}{(3x+2)^2}[/tex]
