PLS HELP:( !! What is an equation of the line
that is perpendicular to the line
y= -2/3x-1 and passes through
the point (-4, 2)?

PLS HELP What is an equation of the line that is perpendicular to the line y 23x1 and passes through the point 4 2 class=

Respuesta :

Answer:

[tex]y = \frac{3}{2} x + 8[/tex]

Step-by-step explanation:

The given equation is written in the form of y=mx+c (where m is the gradient and c is the y-intercept).

Thus, gradient of given equation= -⅔

The products of the gradient of perpendicular lines is -1.

(Gradient of line)(-⅔)= -1

Gradient of line

[tex] = - 1 \div ( - \frac{2}{3} ) \\ = \frac{3}{2} [/tex]

Hence, m= [tex] \frac{3}{2} [/tex].

Subst. m= [tex] \frac{3}{2} [/tex]into the equation:

[tex]y = \frac{3}{2} x + c[/tex]

To find the value of c, substitute a pair of coordinates into the equation:

When x= -4, y= 2,

[tex]2 = \frac{3}{2} ( - 4) + c \\ 2 = - 6 + c \\ c = 2 + 6 \\ c = 8[/tex]

Thus, the equation of the line is [tex]y = \frac{3}{2} x + 8[/tex].

Y=3/2 because It passes through the point