Answer:
0.962 atm.
97.4 kPa.
731 torr.
14.1 psi.
97,434.6 Pa.
Explanation:
Hello.
In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:
- Atmospheres: 1 atm = 760 mmHg:
[tex]p=731mmHg*\frac{1atm}{760mmHg} =0.962atm[/tex]
- Kilopascals:: 101.3 kPa = 760 mmHg:
[tex]p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa[/tex]
- Torrs: 760 torr = 760 mmHg:
[tex]p=731mmHg*\frac{760 torr}{760mmHg} =731 torr[/tex]
- Pounds per square inch: 14.69 psi = 760 mmHg:
[tex]p=731mmHg*\frac{14.69}{760mmHg} =14.1psi[/tex]
- Pascals: 101300 Pa = 760 mmHg:
[tex]p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa[/tex]
Best regards.