Answer:
Let's see what to do buddy...
Explanation:
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[tex]a = \frac{60}{ ({ \frac{1}{5}) }^{2} } = \frac{60}{ \frac{1}{25} } = 60 \times 25 \\ \\ a = 15 \times 4 \times 25 = 15 \times 100 \\ a = 1500 \: \frac{m}{ {s}^{2} } [/tex]
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The body start from rest which means :
[tex]v(0) = 0[/tex]
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In third second means :
t = 2 -----¢ t = 3 -----¢ ∆t = 1
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We have this equation to find the distance.
[tex] ∆x = \frac{1}{2} \: a \: {t}^{2} + v(0) \: t \\ [/tex]
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[tex]∆x = \frac{1}{2} \times 1500 \times 1 + 0 \times 1 \\ \\ ∆x = 750 + 0 = 750[/tex]
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And we're done.
Thanks for watching buddy good luck.
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