For this exercise it has to be taken the leaning curve with a leaning rate equals to L%
If the period necessary for 1st unit is equal to T,
the time necessary for the 2nd unid is equal to L/100 * T
as well as for the forth it will be L/100^2T
As explained,
The necessary time for the first unit will be 9 hours
and the second it will be 6.3 hours
applying the Leaning method we have
= (2nd necessary time/1st necessary time )* 100 = 6.3h/9h*100 = 70%
therefore the modifications performed by six mechanics is equal to 300/6 which is equal to 50 modifications
By using the leaning curve, it has to be found the total amount of time necessary for each mechanic to perform the 50 modifications.
50th modification time = 1.2 hour
therefore the total time necessary to perform the 50th modifications is equal to 110.76 h
So, the time for each modification is equal to:
110.76 h / 50 = 2.21 h