Step-by-step explanation:
a. We have v as the amount of drug(mg) in the blood at time t (hrs)
b. Flow rate in = k litre/he
For a circulatory system we have the flow rate in and flow rate out to be the same
Therefore,
Flow rate out = k litre/hr
concentration of drug going in = 0mg/litre
Concentration of drug going out = v mg/litre
V(0) = 20mg since 20mg was taken at midnight
V(0) = 20
Half life t1/2 = 36 hours
V(36) = v(0)/2
= 20/2
= 10mg
C. [tex]ivp = \frac{dv}{dt}[/tex][tex]= -kv[/tex]
[tex]v(0) = 20mg\\v(36) = 10mg[/tex]
d. solution
[tex]\frac{dv}{dt} = -kt\\ln(v) = ln(c) - kt[/tex]
[tex]\frac{v}{c} = e^{-kt} = v=ce^{-kt}[/tex]
v(0) = 20
[tex]ce^{-k(0)} =20[/tex]
c = 20
so
[tex]v(t) = 20e^{-kt}[/tex]
e.
[tex]t\frac{1}{2}=36hours\\ v(36)= 10[/tex]
[tex]10 = 20e^{-36k}[/tex]
[tex]\frac{1}{2} =e^{-36k}[/tex]
we take log
[tex]k=\frac{ln(2)}{36}[/tex]
please check attachment for answer f