Respuesta :
Answer:
The answer is "5 users and 1 block".
Explanation:
In Option a:
Bandwidth total [tex]= 1-Gbps \times 1000[/tex]
[tex]= 1,000 \ Mbps[/tex]
Any User Requirement [tex]= 200 \ Mbps[/tex]
The method for calculating the number of approved users also is:
Now, calculate the price of each person for overall bandwidth and demands,
[tex]\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}[/tex]
[tex]=\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users[/tex]
In Option b:
[tex]\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}[/tex]
[tex]\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}[/tex]
[tex]= \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\[/tex]
mean user [tex]= 25 \times \frac{1}{20} \\\\[/tex]
[tex]= 1.25[/tex]
max user [tex]= \frac{10^9}{40 \times 10^6} \\\\[/tex]
[tex]= \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\[/tex]
