Answer:
Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong):
a) a×b = 34.27k
b) a·b = 128.43
c) (a + b)·b = 305.17
d) The component of a along the direction of b = 9.66
Explanation:
Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong) we can proceed as follows:
a) The vectorial product, a×b is:
[tex] a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k [/tex]
b) The escalar product a·b is:
[tex] a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43 [/tex]
c) Asumming (a + b)·b instead a+b·b we have:
[tex](a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17[/tex]
d) The component of a along the direction of b is:
[tex] a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66 [/tex]
I hope it helps you!
