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Work out an equation of the straight line with gradient 3 that passes through the point with coordinates (2, 4).

Respuesta :

Answer:

The answer is

[tex] \huge \boxed{y = 3x - 10}[/tex]

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

[tex]y - y_1 = m(x - x_1)[/tex]

where

m is the slope

( x1 , y1) is the point

From the question the point is (2, 4) and the slope is 3

The equation of the line is

[tex]y - 4 = 3(x - 2) \\ y + 4 = 3x - 6 \\ y = 3x - 6 - 4[/tex]

We have the final answer as

[tex]y = 3x - 10[/tex]

Hope this helps you