Given:
[tex]-3x+2b>8[/tex]
To find:
The value of x.
Solution:
We have,
[tex]-3x+2b>8[/tex]
To find the value of x, we need to isolate x on one side.
Subtract 2b from both sides.
[tex]-3x>8-2b[/tex]
Divide both sides by -3. On multiplying or dividing an inequality by a negative number, we need to change the sign of inequality.
[tex]\dfrac{-3x}{-3}<\dfrac{8-2b}{-3}[/tex]
[tex]x<\dfrac{-2b+8}{-3}[/tex]
The required inequality for x is [tex]x<\dfrac{-2b+8}{-3}[/tex].
Therefore, the correct option is A.
