A 450.0 kg boat experiences two simultaneous forces. The motor exerts a force of 100.0 N to accelerate the boat forward, while an unknown drag force pushes in the opposite direction. The boat accelerates forward at 0.1330 m/s2. Calculate the drag force acting on the boat.

Respuesta :

Answer:

The  drag force is [tex]D = 40.15 \ N[/tex]

Explanation:

From the question we are told that

  The mass is  [tex]m = 450.0 \ kg[/tex]

  The acceleration [tex]a  = 0.133 m/s^2[/tex]

The force due to the motor is  [tex]F_m = 100 \ N[/tex]

Generally the net force acting on the boat is mathematically represented as

    [tex]F = m * a[/tex]

=>  [tex]F = 450.0 * 0.1330[/tex]

=>  [tex]F = 59.85 \ N[/tex]

Generally the drag force acting on the boat is mathematically represented as

     [tex]D = F_m -F[/tex]

=>  [tex]D = 100 - 59.85[/tex]

=>   [tex]D = 40.15 \ N[/tex]