Respuesta :
Given:
Initial height of tree = [tex]7\dfrac{11}{12}[/tex] foot
He cut [tex]1\dfrac{2}{3}[/tex] off of tree.
To find:
The remaining height of tree after cut.
Solution:
Initial height of tree is
[tex]7\dfrac{11}{12}=\dfrac{7\times 12+11}{12}[/tex]
[tex]7\dfrac{11}{12}=\dfrac{84+11}{12}[/tex]
[tex]7\dfrac{11}{12}=\dfrac{95}{12}[/tex]
He cut [tex]1\dfrac{2}{3}[/tex] off of tree.
[tex]1\dfrac{2}{3}=\dfrac{1\times 3+2}{3}[/tex]
[tex]1\dfrac{2}{3}=\dfrac{3+2}{3}[/tex]
[tex]1\dfrac{2}{3}=\dfrac{5}{3}[/tex]
Now,
Remaining height = Initial height - cut
[tex]=\dfrac{95}{12}-\dfrac{5}{3}[/tex]
[tex]=\dfrac{95-20}{12}[/tex]
[tex]=\dfrac{75}{12}[/tex]
[tex]=\dfrac{25}{4}[/tex]
[tex]=\dfrac{6\times 4+1}{4}[/tex]
[tex]=6\dfrac{1}{4}[/tex]
Therefore, the remaining height of the tree is [tex]6\dfrac{1}{4}[/tex] foot.
