Answer:
a. N(t) = 1.25 (1/2)^t/7
b. 0.1160933038mg.
Step-by-step explanation:
The formula for half life =
N(t) = No(1/2)^t/t½
Where N(t) = Amount of Substance left
No = Initial amount not Substance
t = time after t years
t½ = Half life of the substance
From the question:
No = 1.25mg
t½ = 7 years
a. Find a model for the amount of albuterol left in the body t hours after an initial dose of 1.25 mg.
N(t) = No(1/2)^t/t½
No = 1.25mg
t½ = 7 years
N(t) = 1.25 (1/2)^t/7
b. How much albuterol is left in the body after 24 hours?
Using the model in the above question
N(t) = 1.25 (1/2)^t/7
N(t) = 1.25(1/2)^24/7
N(t) = 1.25(0.5)^3.4285714286
N(t) = 0.1160933038mg
Therefore, the quantity of albuterol left in the body after 24 hours is 0.1160933038mg.
