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A ball is dropped from the top of a building and hits the street below in 4.25 s. How tall is the building? Show work for brainliest.

Respuesta :

Answer:

90.3125 m

Explanation:

[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]

a = 10m/s^2 (constant)

S=height

U=initial velocity

a= gravitational acceleration

t= time

s = 0 + 1/2 * 10 * 4.25 ^2

u is 0 because it is dropped without velocity

s =90.3125 m

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