SP1b.
During a 5.0 second interval, an object's velocity changes from 25 meters per second
east to 15 meters per second east. Determine the magnitude and direction of the
object's acceleration.

Respuesta :

Answer:

2 m/s^2, west

Explanation:

Vf=final velcoity

Vi=initial velocity

t=timw

[tex]a = \frac{vf - vi}{t} [/tex]

=

[tex] \frac{15 - 25}{5} [/tex]

= - 2 m/s^2

The - changes direction and makes it opposite

2 m/s, west

The magnitude of the object acceleration is -2m/s². Since the acceleration of the object is negative, hence the direction will be towards the west

Acceleration is the change in velocity of a body with respect to time. Mathematically;

[tex]a=\frac{v-u}{t}[/tex]

v is the final velocity

u is the initial velocity

t is the time taken;

Given the following parameters

v = 15m/s

u = 25m/s

t = 5.0secs

Substitute the given parameters into the formula to have:

[tex]a=\frac{15-25}{5}\\a=\frac{-10}{5}\\a=-2m/s^2[/tex]

Hence the magnitude of the object acceleration is -2m/s². Since the acceleration of the object is negative, hence the direction will be towards the west.

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