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The amino acids in the original partial sequence (N-term-...P-I-E...-C-term) have little to no impact on protein structure and function. However the amino acid sequence near the C-terminal end of the protein is required for normal function. Any amino acid changes in this region of the protein will result in a nonfunctional protein. Given this information, which reversion mutation in the gene would restore the normal function of the protein?

a. Insertion of 2 base-pairs in the region of the proline codon
b. Deletion of 5 base-pairs in the region of the proline codon
c. Deletion of 2 base-pairs in the region of the proline codon
d. Deletion of 1 base-pair in the region of the proline codon
e. Insertion of 1 base-pair in the region of the proline codon
f. Insertion of 4 base-pairs in the region of the proline codon

Respuesta :

batolisis

Answer:

OPTIONS : B,C,E,F

Explanation:

The Reversion mutation in the gene that would restore the normal function of the protein :

All the options given can restore the normal function except options : A and D

For Deletion of 5 base-pairs in the region of the proline codon

      Normal sequence 5' - G | CCG | AUC | GAA | CU - 3' while the mutated sequence is : 5' - G | CCG | AUG | AAC | U - 3' . this shows that the removal of the 5 case pairs will only remove 2 amino acids restoring the normal protein in the process and not affect the C terminal of the amino acids and also the reading frame will be restored  

normal protein.

For Deletion of 2 base-pairs in the region of the proline codon

The Normal sequence 5' - G | CCG | AUC | GAA | CU - 3'  while Mutated sequence 5' - G | CCG | AUG | AAC | U - 3'

This shows that the deleted  base pair is from this codon hence removing the two base pairs will lead to  the reading frame  been restored and also the C terminal amino acids, but this will result to a protein with a less than one amino acid

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