Respuesta :
Explanation:
The energy of electromagnetic radiation is given by :
[tex]E=h\nu[/tex]
Where, h is the Planck's constant
(a) A gamma ray, [tex]\nu = 1.64\times 10^{20}\ Hz[/tex]
Energy,
[tex]E=6.63\times 10^{-34}\times 1.64\times 10^{20}\\E=1.08\times 10^{-13}\ J[/tex]
(b) A microwave, [tex]\nu = 4.95\times 10^{10}\ Hz[/tex]
Energy,
[tex]E=6.63\times 10^{-34}\times 4.95\times 10^{10}\\E=3.28\times 10^{-23}\ J[/tex]
(c) A AM radio wave, [tex]\nu = 2\times 10^{6}\ Hz[/tex]
Energy,
[tex]E=6.63\times 10^{-34}\times 2\times 10^{6}\\E=1.32\times 10^{-27}\ J[/tex]
Therefore, this is the required solution.
