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Answer: A certain element exists as three different isotopes. 24.1% of all the isotopes have a mass of 75.23 amu, 48.7% have a mass of 74.61 amu, and 27.2% have a mass of 75.20 amu. What is the average atomic mass of this element?
Explanation: A certain element exists as three different isotopes. 24.1% of all the isotopes have a mass of 75.23 amu, 48.7% have a mass of 74.61 amu, and 27.2% have a mass of 75.20 amu. What is the average atomic mass of this element? 74.92 amu. Use your periodic table to determine which element this is. As. An element exists
The average atomic mass of the element is 74.93 amu
Let the 1st isotope be A
Let the 2nd isotope be B
Let the 3rd isotope be C
From the question given above, the following data were obtained:
For A (i.e 1st isotope)
Abundance of A (A%) = 24.1%
Mass of A = 75.23 amu
For B (i.e 2nd isotope)
Abundance of B (B%) = 48.7%
Mass of B = 74.61 amu
For C (i.e 3rd isotope)
Abundance of C (C%) = 27.2%
Mass of C = 75.23 amu
Average atomic mass =?
The average atomic mass of the element can be obtained as follow:
Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]
= [(75.23 × 24.1)/100] + [(74.61 × 48.7)/100] + [(75.23 × 27.2)/100]
= 18.13043 + 36.33507 + 20.46256
Average atomic mass = 74.93 amu
Thus, the average atomic mass of the element is 74.93 amu
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