Assuming it takes off from rest, the runway should have length x such that
(148 m/s)² - 0² = 2 (3 m/s²) x
which follows from the formula,
v² - u² = 2 a ∆x
(where u is initial speed and v is final speed; the other two's significance should be obvious)
Solve for x :
x = (148 m/s)² / (2 (3 m/s²))
x ≈ 3650.67 m
