[tex]f(x) = \frac{1}{9}x + 2 \\ [/tex]
[tex]y = \frac{1}{9}x + 2 \\ [/tex]
Subtract the sides of the equation minus 2
[tex]y - 2 = \frac{1}{9}x \\ [/tex]
Multiply the sides of the equation by 9
[tex]9(y - 2) = x[/tex]
[tex]9y - 18 = x[/tex]
So ;
[tex] {f}^{ - 1}(x) = 9x - 18 [/tex]
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And we're done.
Thanks for watching buddy good luck.
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