A building's 10th floor (34.5 m high) is blazing with fire. A fire truck arrived at the scene and the fire
men shoots water from their hose. The water leaves the hose at the speed of 29 m/s, at an angle
of
63° and is held at 0.90 m from the ground. Will the water reach the fire? If so, how far from the
building should the hose be so the fire could be put out? ​

Respuesta :

Answer:

Yes, the water will be reach the fire.

The hose should be at 34.7 m from the building

Explanation:

Given that,

Height of building's =34.5 m

Speed = 29 m/s

Angle = 63°

Distance from the ground = 0.90 m

We need to calculate the actual height

Using formula of height

[tex]H=\dfrac{u^2\sin^2\theta}{2g}[/tex]

Put the value into the formula

[tex]H=\dfrac{29^2\sin^2{63}}{2\times9.8}[/tex]

[tex]H=34.0\ m[/tex]

The height from the ground will be

[tex]H'=34+0.90[/tex]

[tex]H'=34.9\ m[/tex]

We can say that, the water gun attained the maximum height that is 0.4 m more than the 10th floor.

So, yes, the water will be reach the fire.

We need to calculate the range

Using formula of range

[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]

Put the value into the formula

[tex]R=\dfrac{29^2\times\sin(2\times63)}{9.8}[/tex]

[tex]R=69.4\ m[/tex]

The house should be at half of R.

[tex]\dfrac{R}{2}=\dfrac{69.4}{2}[/tex]

[tex]\dfrac{R}{2}=34.7\ m[/tex]

Hence, Yes, the water will be reach the fire.

The hose should be at 34.7 m from the building