Answer:
The answer is no solutions.
Step-by-step explanation:
use systems of equations!
first, rewrite both equations so that the sum or difference includes the same variable.
[tex]9-4x=6y\\-4+2x=-3y[/tex]
notice how i made sure the coefficients that have x and y respectively line up.
with this, i can cancel out the x variables by making 2, and -4 as -8 (8+-8=0).
rewrite the equation.
[tex]2(9-4x=6y)\\4(-4+2x=-3y)\\[/tex]
distribute.
[tex]18-8x=12y\\-16+8x=-12y[/tex]
now we can successfully cancel out the x variable!
[tex]18=12y\\-16=-12y[/tex]
uh oh! it seems we can also cancel out the y variables..
[tex]18=0\\-16=0[/tex]
18 is not equal to 0 and neither is -16. because of this, we can conclude there is no solution for this system of equations.
hope this helps!!
