Answer:
C, D
Step-by-step explanation:
This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.
For ax² +bx +c = 0, the solutions are ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
In the given equation, a=2, b=11, c=5, so this becomes ...
[tex]x=\dfrac{-11\pm\sqrt{11^2-4\cdot2\cdot5}}{2\cdot2}=\dfrac{-11\pm\sqrt{81}}{4}\\\\x=\dfrac{-11\pm9}{4}=\left\{-\dfrac{20}{4},-\dfrac{2}{4}\right\}=\{-5,-\frac{1}{2}\}[/tex]
The solutions are ...
C. x = -5
D. x = -1/2
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My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.
