Answer:
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
Explanation:
Given data:
Mass of glucose = 10 g
Mass of oxygen required for complete combustion = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
Now we will convert the given mass of glucose into number of moles.
Number of moles = mass/ molar mass
Number of moles = 10 g/ 180.156 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
0.06 : 6×0.06 = 0.36 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Number of moles = 0.36 mol × 32 g/mol
Number of moles = 11.52 g
For the complete combustion of 10 g of glucose 11.52 g of oxygen is required.
