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a cheerleader throws herself into the air with a velocity of 12 m/s at an angle of 75 degrees above the horizontal. what are the x- and y components of her velocity (show work)

Respuesta :

rafaleo84

Answer:

Vx = 3.10 [m/s]

Vy = 11.59 [m/s]

Explanation:

To solve this problem we must decompose the velocity vector by means of the angle on the horizontal.

v = 12 [m/s]

Vx = 12*cos (75) = 3.10 [m/s]

Vy = 12*sin (75) = 11.59 [m/s]

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