Answer:
An increase in the mass on the string will cause an increase in the period.
Explanation:
We'll begin by writing an expression showing the relationship between the period and mass. This is shown below:
T = 2π√(m/K)
Where:
T is the period of oscillation.
m is the mass of the object.
K is the spring constant.
T = 2π√(m/K)
From the above formula:
The period (T) is directly proportional to the square root of mass (m) and inversely proportional to the square root of the spring constant (K). This implies that an increase in the mass of the object on the spring will result in an increase in the period of oscillation and a decrease in the mass of the object will also decrease the period of oscillation.
