Answer:
Theoretical yield of CaCO₃ is 2.002 g.
Explanation:
Given data:
Mass of K₂CO₃ = 2.5 g
Mass of CaCl₂ = 2 g
Theoretical yield of CaCO₃ = ?
Solution:
Chemical equation:
K₂CO₃ + CaCl₂ → CaCO₃ + 2KCl
Number of moles of K₂CO₃:
Number of moles = mass/molar mass
Number of moles = 2.5 g/ 138.205 g/mol
Number of moles = 0.02 mol
Number of moles of CaCl₂:
Number of moles = mass/molar mass
Number of moles = 2 g/ 110.98 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of CaCO₃ with K₂CO₃ and CaCl₂.
CaCl₂ : CaCO₃
1 : 1
0.02 : 0.02
K₂CO₃ : CaCO₃
1 : 1
0.02 : 0.02
Theoretical yield of CaCO₃:
Mass = number of moles × molar mass
Mass = 0.02 mol × 100.1 g/mol
Mass = 2.002 g
Theoretical yield of CaCO₃ is 2.002 g.
