Answer:
[tex]T_{ - 5 ,
8} \: or \: D'(x,y) →D(x - 5,y + 8)[/tex]
Step-by-step explanation:
[tex]T _ { ? ,
?}[/tex]
[tex]D'(x,y) →D(x \pm ?,y \pm ?)[/tex]
given D : (7,-3), and D' : (2,5)
the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).
you can simply take the difference in the x values and difference in the y values from the preimage to image.
like this:
f'(x,y) → f(x+(x-x1),y+(y-y1)) : [tex]
T _ {(x-x_1),(y-y_1)}[/tex]
D'(x,y) → D(x+(2-7),y+(5--3))
D'(x,y) → D(x-5,y+8) : [tex]
T _ {-5 ,8}[/tex]
