No. 5, Given BCM=ZYR, find each missing measure. Will mark brainliest!

Answer:
Step-by-step explanation:
Since, ΔBCM ≅ ΔZYR,
∠B ≅ ∠Z
∠C ≅ ∠Y
∠M ≅ ∠R
And BC ≅ ZY
CM ≅ YR
BM ≅ ZR
a). CM = YR = 11 m
b). BM = RZ = 15 m
c). YZ = BC = 8 m
d). m∠B = m∠Z = 45°
e). m∠M = 180° - [m(∠B) + m(∠C)]
= 180° - (45 + 103)°
= 180° - 148°
= 32°
f). m∠Y = m∠C = 103°
Congruent triangles have equal corresponding sides and angles
The given parameter is:
[tex]\triangle BCM \cong \triangle ZYR[/tex]
This means that triangle BCM and ZYR are congruent.
So, we have the following congruent sides
[tex]YZ =CB[/tex]
[tex]BM =ZR[/tex]
[tex]CM =YR[/tex]
So, the measure of the side lengths are:
[tex]YZ =8[/tex]
[tex]BM =15[/tex]
[tex]CM = 11[/tex]
Also, we have the following congruent angles
[tex]\angle B = \angle Z[/tex]
[tex]\angle C = \angle Y[/tex]
[tex]\angle M = \angle R[/tex]
So, the measure of the angles are
[tex]\angle B =45[/tex]
[tex]\angle Y =103[/tex]
The measure of angle M is calculated using:
[tex]\angle M + \angle C + \angle B = 180[/tex]
So, we have:
[tex]\angle M + 103 + 45= 180[/tex]
[tex]\angle M + 148= 180[/tex]
Subtract 148 from both sides
[tex]\angle M = 32[/tex]
Read more about congruent triangles at:
https://brainly.com/question/11329400