Answer:
A) Godric can have maximum of four $20 bills.
Therefore Godric can not have five $20 bills.
B) Equation is:
[tex]5n+20(11-n)=115[/tex]
[tex]n=7[/tex]
Step-by-step explanation:
Let the number of $5 bills with Godric = [tex]n[/tex]
Total number of bills = 11
Therefore, number of $20 bills = (11 - [tex]n[/tex])
Total amount of money in form of $5 bills = $[tex]5n[/tex]
Total amount of money in form of $20 bills = $[tex]20(11-n)[/tex]
Total money with Godric is $115.
[tex]\therefore 5n+20(11-n)=115\\\Rightarrow -15n=115-220\\\Rightarrow n=7[/tex]
Number of $5 bills present with Godric = 7
Number of $20 bills present with Godric = 11 - 7 = 4
A) Godric can have maximum of four $20 bills.
Therefore Godric can not have five $20 bills.
B) Equation is:
[tex]5n+20(11-n)=115[/tex]
Solution is [tex]n=7[/tex]
