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Diagonals of a parallelogram ABCD intersect at O. If∠BOC = 90º and ∠BDC = 50º, then ∠OAB is (A) 90º (B) 50º (C) 40º (D) 10º​

Respuesta :

didiiryadi07011977

Answer:

diagonals

lf= Boc =90°

Bcd = 50°

QAB (A) ? jadi jawaban nya

(D). 10°

Step-by-step explanation:

Diognals of a Parallegram ABCD intersat at o

lg and then is.

"sorry ya kalo jawaban nya salah "

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