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The first aircraft has 89 more seats than the second aircraft. The third aircraft has 45 fewer seats than the second aircraft. If their total number of seats is 401, find the number of seats for each aircraft

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Answer:  The first aircraft has 208 seats.

The second aircraft has 119 and the third has 74.

Step-by-step explanation:

The equation is x+89 + x + x-45 = 401

combine terms: 3x + 44 = 401  Subtract 44 from both sides  3x=357  

divide both sides by 3

x= 119

substitute x in each term of the equation to find the number of seats on each aircraft

119 + 89 = 208 for #1    x= 119 for #2    119- 45= 74 for #3

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