How many times do you need to regroup to add 873 + 465 ? Explain .

To find the answer to this question, we need to add the numbers according to their place. Etc if 1 and 4 are together in a hundreds place, we add them together. If both numbers add up together results in a number bigger than 9, we have to regroup.

First, let us find the ones place.

3+5=8

Since the result is not more than 9, we do not have to regroup.

Secondly, we find the tens place.

7+6=13

Since the result is more than 9, we have to regroup.

Regrouping counter:1

Thirdly, we find the hundreds place.

8+4=12

Regrouping counter:2

Hence, your final answer is 2.

fichoh fichoh · Answer 2 · 2021-09-02T14:02:12+02:00

The number of times we need to group when summing 873 and 465 is 2.

During addition of two numbers, values are added based on their place values, such that digits with the same place value are added together.

The highest single value that can be obtained when summing values without needing to regroup is 9.

Hence, each time two digits are added such that the value of the sum exceeds 9, then regrouping is required.

Adding 873 + 465

H __ T __ U

8 __ 7 __ 3

4 __ 6 __ 5

(3 + 5) = 8 ( NO NEED TO REGROUP)

7 + 6 = 13 (WE NEED TO REGROUP) SUM exceed 9

(8 + 4 + 1) = 13 (WE NEED TO REGROUP) SUM exceed 9

Hence, the number of times we need to regroup is 2.

Learn more : https://brainly.com/question/5117026