Answer:
[tex]\frac{3}{7}[/tex]
Explanation:
Lets take the numerator of the fraction to be = x
So the denominator of the fraction is 4 more than the numerator = x+4
The fraction is ;[tex]\frac{x}{4+x}[/tex]
Now add 4 to the numerator and add 7 to the denominator as;
[tex]\frac{x+4}{4+x+7} =\frac{x+4}{x+11}[/tex]
This new fraction is equal to 1 half =1/2
write the equation as;
[tex]\frac{x+4}{x+11} =\frac{1}{2}[/tex]
perform cross-product
2(x+4 )=1( x+11 )
2x+8 = x + 11
2x-x = 11-8
x=3
The original fraction is;
[tex]\frac{x}{4+x} =\frac{3}{3+4} =\frac{3}{7}[/tex]
