Step-by-step explanation:
Hey there!
Here;
The equations are:
3x + 4y - 7 = 0.............(I)
6x + 8y -11 = 0.........(ii)
Let's simply work with this.
From equation (I)
[tex]slope(m) = \frac{ - coeff.of \: x}{coeff.of \: y} [/tex]
[tex]m1 = \frac{ - 3}{4} [/tex]
From equation (ii)
[tex]slope(m2) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y} [/tex]
[tex]m2 = \frac{ - 6}{8} [/tex]
[tex]m2 = \frac{ - 3}{4} [/tex]
As per the condition of parallel lines;
M1 = M2
-3/4 = -3/4. (true)
Therefore, the lines are parallel to eachother.
Hope it helps...
