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In triangle ABC, it is given that A = 70 degree, B = 52 degree, BO and CO are the bisectors of angle B and angle C
respectively. Find angle OCB andangle BOC.

Respuesta :

Parthchaudhari

Answer:

Angle OCB= 35 degrees and Angle BOC= 119

Step-by-step explanation:

ANGLE OCB= 1/2 C (Construction of bisector)

= 1/2 70

= 35

ANGLE OBC= 1/2 B (Construction of bisector)

= 1/2 52

= 26

Therefore, in triangle BOC,

180 degree= ANGLE OBC+ANGLE BOC+ANGLE OCB

180= 35+26+ANGLE BOC

180= 61+ANGLE BOC

ANGLE BOC= 180-61

ANGLE BOC= 119

ekamunya04

Answer:

angle ocb=58°

angleboc=96°

Step-by-step explanation:

first get the measure of angle acb which is 58°

this is becoz the total angles in a triangle add up to 180°

angle cbo =26° and angle bco=58°

therefore to get the remaining angle boc ,u add 58 &26 ,then minus from 180

the answer is 96°

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