Answer:
The probability will be "0.26938".
Explanation:
The given value is:
Mean
[tex]\mu = 1.8[/tex]
By using Poisson probability formula, we get
⇒ [tex]P(X = x) = \frac{ (e-\mu\times \mu x )}{x!}[/tex]
⇒ [tex]P(X > 2) = 1 - P(X \leq 2)[/tex]
⇒ [tex]1 - (P(X = 0) + P(X = 1) + P(X = 2))[/tex]
⇒ [tex]1 - (e-1.8 * 1.80) / 0! + e-1.8 * 1.81) / 1! + e-1.8 * 1.82) / 2! )[/tex]
⇒ [tex]1 - 0.73062[/tex]
⇒ [tex]0.26938[/tex]