Respuesta :
Answer:
4.93 seconds
Step-by-step explanation:
The height y in feet of water t seconds after its release is given by the equation as follows :
[tex]y=-16t^2-2t+400[/tex]
We need to find the taken taken for the water to reach the ground. When it reach the ground, y will be equal to 0. So,
[tex]-16t^2-2t+400=0[/tex]
Above is a quadratic equation whose solutions can be calculated as follows :
[tex]t=\dfrac{-(-2)\pm \sqrt{(-2)^2-4\times (-16)\times 400} }{2\times (-16)}\\\\t=\dfrac{-(-2)+ \sqrt{(-2)^2-4\times (-16)\times 400} }{2\times (-16)}, \dfrac{-(-2)- \sqrt{(-2)^2-4\times (-16)\times 400} }{2\times (-16)}\\\\t=-5.062\ s\ \text{and}\ 4.93\ s[/tex]
Neglecting negative value.
Hence, it will take 4.93 seconds for the water to reach the ground
