[tex]f(x) = \frac{1}{3}x - 4 \\ [/tex]
[tex]y = \frac{1}{3}x - 4 \\ [/tex]
Subtract the sides of the equation plus 4
[tex]y + 4 = \frac{1}{3}x \\ [/tex]
Multiply the sides of the equation by 3
[tex]3(y + 4) = x[/tex]
[tex]3y + 12 = x[/tex]
So ;
[tex] {f}^{ - 1}(x) = 3x + 12 [/tex]
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And we're done.
Thanks for watching buddy good luck.
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