Answer:
4.50 L gas of fluorine at STP contain 0.2 moles.
Explanation:
Given data:
Volume of gas = 4.50 L
Number of moles F₂ gas = ?
Temperature of gas = standard = 273.15 K
Pressure of gas = standard = 1 atm
Explanation:
Formula:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values in formula.
1 atm × 4.50 L = n × 0.0821 atm.L/ mol.K × 273.15 K
4.50 atm.L = n × 22.43 atm.L/ mol.
n = 4.50 atm.L / 22.43 atm.L/ mol.
n = 0.2 mol
4.50 L gas of fluorine at STP contain 0.2 moles.
