Answer:
First even integer: 6
Step-by-step explanation:
Inequalities
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:
[tex]x+x+2<3(x+4)-15[/tex]
Operating:
[tex]2x+2<3x+12-15[/tex]
Subtracting 2 and 2x:
[tex]0<3x+12-15-2x-2[/tex]
Simplifying:
[tex]0<x-5[/tex]
Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.
