Answer:
The value is [tex]H =0.3966[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The mean tail is [tex]\= x = 85.4 \cm[/tex]
The number of resplendent quetzals selected as breeders is [tex]k = 10[/tex]
The mean tail breeders is [tex]\= x_1 = 91.2 \ cm[/tex]
The mean tail of the breeders after mating [tex]\= x_2 = 87.7 \ cm[/tex]
Generally the selection differential is mathematically represented as
[tex]D = \= x_1 - \= x [/tex]
=> [tex]D = 91.2- 85.4 [/tex]
=> [tex]D = 5.8 \ cm [/tex]
Generally the selection response is mathematically represented as
[tex]S = \= x_2 - \= x[/tex]
=> [tex]S = 87.7 - 85.4[/tex]
=> [tex]S =2.3 \ cm [/tex]
Generally the heritability of tail length in this resplendent quetzal population is mathematically represented as
[tex]H = h^2 = \frac{S}{D} [/tex]
=> [tex]H = h^2 = \frac{2.3}{5.8} [/tex]
=> [tex]H = h^2 = \frac{2.3}{5.8} [/tex]
=> [tex]H = h^2 = 0.3966/tex]
