Answer:
2.405 m/s
Explanation:
Given that,
Mass of a women, m₁ = 60 kg
Mass of a ball, m₂ = 3.9 kg
Velocity of the ball, v₂ = 37 m/s
We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,
[tex]m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s[/tex]
So, the velocity of the woman is 2.405 m/s.
