Respuesta :
Answer:
3.4
Explanation:
Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: 2 HNO₃(aq) + NO(g) ⇄ 3 NO₂(g) + H₂O(l)
At a certain temperature, a chemist finds that a 9.5L reaction vessel containing a mixture of nitric acid, nitrogen monoxide, nitrogen dioxide, and water at equilibrium has the following composition:
compound amount
HNO₃ 15.5g
NO 16.6g
NO₂ 22.5g
H₂O 189.0g
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.
Step 1: Write the balanced equation.
2 HNO₃(aq) + NO(g) ⇄ 3 NO₂(g) + H₂O(l)
Step 2: Calculate the molar concentration of the species at equilibrium
We will use the following expression.
M = mass of solute / molar mass of solute × liters of solution
[HNO₃] = 15.5g / 63.01 g/mol × 9.5 L = 0.026 M
[NO] = 16.6g / 30.01 g/mol × 9.5 L = 0.058 M
[NO₂] = 22.5g / 46.01 g/mol × 9.5 L = 0.051 M
We do not calculate the molarity of water because it is a pure liquid and will not be included in the equilibrium constant.
Step 3: Calculate the equilibrium constant (Kc)
Kc = [NO₂]³/[HNO₃]²×[NO]
Kc = 0.051³/0.026²×0.058
Kc = 3.4